|
PROGRAM TEST
|
IMPLICIT NONE
|
C
|
INTEGER LDB, LDWORK, LDX, N, NRHS
|
PARAMETER (N = 4)
|
PARAMETER (LDB = N)
|
PARAMETER (LDWORK = 2 * N)
|
PARAMETER (LDX = N)
|
PARAMETER (NRHS = 1)
|
C
|
DOUBLE PRECISION B(LDB,NRHS), BERR(NRHS), DIAG(N)
|
DOUBLE PRECISION DIAGF(N), DLOW(N-1), DLOWF(N-1), EPSLON
|
DOUBLE PRECISION FERR(NRHS), WORK(LDWORK), X(LDX,NRHS)
|
INTEGER ICOL, INFO, IROW
|
C
|
EXTERNAL DCOPY, DPTCON, DPTRFS, DPTTRF, DPTTRS
|
INTRINSIC ABS, MAX
|
C
|
C Initialize the arrays DLOW, DIAG, and DUP1 to store
|
C the first subdiagonal, the diagonal, and the first
|
C superdiagonal of the symmetric coefficient matrix A
|
C shown below. Initialize the array B to store the right
|
C hand side matrix b shown below.
|
C
|
C 0 0 30
|
C A = 0 2 2 b = 50
|
C 2 2 0 70
|
C 0 0 110
|
C
|
DATA DLOW / 0.0D0, 2.0D0, 0.0D0 /
|
DATA DIAG / 0.0D0, 2.0D0, 2.0D0, 0.0D0 /
|
DATA B / 3.0D1, 5.0D1, 7.0D1, 1.1D2 /
|
C
|
C Add a small value to each of the elements on the diagonal
|
C and subtract the same value from the first sub- and
|
C super-diagonal of A. After this loop, A will resemble the
|
C matrix shown below. Print A after adding epsilon.
|
C
|
C -e -e
|
C A = -e 2+e 2-e
|
C 2-e 2+e -e
|
C -e -e
|
C
|
EPSLON = ABS ((((2.0D0 / 3.0D0) + 4.0D0) - 4.0D0) -
|
$ (2.0D0 / 3.0D0))
|
DO 100, IROW = 1, N - 1
|
DLOW(IROW) = DLOW(IROW) - EPSLON
|
DIAG(IROW) = DIAG(IROW) + EPSLON
|
100 CONTINUE
|
DIAG(N) = DIAG(N) + EPSLON
|
CALL DCOPY (N - 1, DLOW, 1, DLOWF, 1)
|
CALL DCOPY (N, DIAG, 1, DIAGF, 1)
|
C
|
PRINT 1000
|
DO 110, IROW = 1, N
|
PRINT 1010, (0.0D0, ICOL = 1, IROW - 2),
|
$ (DLOW(ICOL + 1), ICOL = ABS(IROW - 2), IROW - 2),
|
$ DIAG(IROW),
|
$ (DLOW(IROW), ICOL = 1, MIN(1, N - IROW)),
|
$ (0.0D0, ICOL = IROW + 2, N)
|
110 CONTINUE
|
C
|
C Slightly perturb each element of B. After this loop, B will
|
C resemble the matrix shown below. Print B afterwards.
|
C
|
C 30+e
|
C B = 50+e
|
C 70+e
|
C 110+e
|
C
|
DO 130, ICOL = 1, NRHS
|
DO 120, IROW = 1, N
|
B(IROW,ICOL) = B(IROW,ICOL) * (1.0D0 - EPSLON)
|
120 CONTINUE
|
130 CONTINUE
|
CALL DCOPY (N, B, 1, X, 1)
|
PRINT 1020
|
PRINT 1030, B
|
C
|
C LDL factor A.
|
C
|
CALL DPTTRF (N, DIAGF, DLOWF, INFO)
|
IF (INFO .LT. 0) THEN
|
PRINT 1040, ABS(INFO)
|
STOP 1
|
ELSE IF (INFO .GT. 0) THEN
|
PRINT 1050, INFO
|
STOP 2
|
END IF
|
C
|
C Solve Ax=b and print the solution.
|
C
|
CALL DPTTRS (N, NRHS, DIAGF, DLOWF, X, LDX, INFO)
|
IF (INFO .NE. 0) THEN
|
PRINT 1060, INFO
|
STOP 3
|
END IF
|
PRINT 1070
|
PRINT 1080, X
|
PRINT 1090
|
PRINT 1030, DIAG(1) * X(1,1) + DLOW(1) *
|
$ X(2,1)
|
PRINT 1030, DLOW(1) * X(1,1) + DIAG(2) * X(2,1) + DLOW(2) *
|
$ X(3,1)
|
PRINT 1030, DLOW(2) * X(2,1) + DIAG(3) * X(3,1) + DLOW(3) *
|
$ X(4,1)
|
PRINT 1030, DLOW(3) * X(3,1) + DIAG(4) * X(4,1)
|
C
|
C Refine the solution to Ax=b and print the refined solution.
|
C
|
CALL DPTRFS (N, NRHS, DIAG, DLOW, DIAGF, DLOWF, B, LDB,
|
$ X, LDX, FERR, BERR, WORK, INFO)
|
IF (INFO .NE. 0) THEN
|
PRINT 1100, ABS(INFO)
|
STOP 4
|
END IF
|
PRINT 1110
|
PRINT 1080, X
|
PRINT 1120
|
PRINT 1030, DIAG(1) * X(1,1) + DLOW(1) *
|
$ X(2,1)
|
PRINT 1030, DLOW(1) * X(1,1) + DIAG(2) * X(2,1) + DLOW(2) *
|
$ X(3,1)
|
PRINT 1030, DLOW(2) * X(2,1) + DIAG(3) * X(3,1) + DLOW(3) *
|
$ X(4,1)
|
PRINT 1030, DLOW(3) * X(3,1) + DIAG(4) * X(4,1)
|
PRINT 1130, FERR(1)
|
PRINT 1140, BERR(1)
|
C
|
1000 FORMAT (1X, 'A:')
|
1010 FORMAT (4(2X, F18.16))
|
1020 FORMAT (/1X, 'b:')
|
1030 FORMAT (1X, F21.17)
|
1040 FORMAT (1X, 'Illegal argument to DPTRFS, argument #', I2)
|
1050 FORMAT (1X, 'A is not positive definite, INFO = ', I2)
|
1060 FORMAT (1X, 'Illegal argument to DPTRFS, argument #', I2)
|
1070 FORMAT (/1X, 'Initial solution to Ax=b:')
|
1080 FORMAT (1X, E25.17)
|
1090 FORMAT (/1X, 'Ax with the initial x:')
|
1100 FORMAT (1X, 'Illegal argument to DPTRFS, INFO = ', I2)
|
1110 FORMAT (/1X, 'Refined solution to Ax=b:')
|
1120 FORMAT (/1X, 'Ax with refined x:')
|
1130 FORMAT (/1X, 'Forward error: ', E14.8)
|
1140 FORMAT (1X, 'Backward error: ', E14.8)
|
C
|
END
|
|